Base | Representation |
---|---|
bin | 1110100100000110111… |
… | …10100110111100011111 |
3 | 1202211200021100211210021 |
4 | 13102003132212330133 |
5 | 31144331020423341 |
6 | 1021520221053011 |
7 | 51103632126535 |
oct | 7220336467437 |
9 | 1684607324707 |
10 | 500422045471 |
11 | 183256220507 |
12 | 80b9a3b7167 |
13 | 3826070a81a |
14 | 1a3132c6155 |
15 | d03cbed9d1 |
hex | 74837a6f1f |
500422045471 has 2 divisors, whose sum is σ = 500422045472. Its totient is φ = 500422045470.
The previous prime is 500422045469. The next prime is 500422045531. The reversal of 500422045471 is 174540224005.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 500422045471 - 21 = 500422045469 is a prime.
It is a super-3 number, since 3×5004220454713 (a number of 36 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
Together with 500422045469, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (500422045171) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 250211022735 + 250211022736.
It is an arithmetic number, because the mean of its divisors is an integer number (250211022736).
Almost surely, 2500422045471 is an apocalyptic number.
500422045471 is a deficient number, since it is larger than the sum of its proper divisors (1).
500422045471 is an equidigital number, since it uses as much as digits as its factorization.
500422045471 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 44800, while the sum is 34.
Adding to 500422045471 its reverse (174540224005), we get a palindrome (674962269476).
The spelling of 500422045471 in words is "five hundred billion, four hundred twenty-two million, forty-five thousand, four hundred seventy-one".
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