Base | Representation |
---|---|
bin | 1001010100101101… |
… | …01011010100011101 |
3 | 110220211211112112221 |
4 | 10222112223110131 |
5 | 40222410224343 |
6 | 2144410225341 |
7 | 235020341506 |
oct | 45226532435 |
9 | 13824745487 |
10 | 5005554973 |
11 | 21395615a1 |
12 | b78425251 |
13 | 61a055163 |
14 | 356b09bad |
15 | 1e46a25ed |
hex | 12a5ab51d |
5005554973 has 2 divisors, whose sum is σ = 5005554974. Its totient is φ = 5005554972.
The previous prime is 5005554971. The next prime is 5005555001. The reversal of 5005554973 is 3794555005.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 4048395129 + 957159844 = 63627^2 + 30938^2 .
It is a cyclic number.
It is not a de Polignac number, because 5005554973 - 21 = 5005554971 is a prime.
Together with 5005554971, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5005554971) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2502777486 + 2502777487.
It is an arithmetic number, because the mean of its divisors is an integer number (2502777487).
Almost surely, 25005554973 is an apocalyptic number.
It is an amenable number.
5005554973 is a deficient number, since it is larger than the sum of its proper divisors (1).
5005554973 is an equidigital number, since it uses as much as digits as its factorization.
5005554973 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 472500, while the sum is 43.
The square root of 5005554973 is about 70749.9468056337. The cubic root of 5005554973 is about 1710.6089703202.
The spelling of 5005554973 in words is "five billion, five million, five hundred fifty-four thousand, nine hundred seventy-three".
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