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50104023143 = 1710192892341
BaseRepresentation
bin101110101010011011…
…101011100001100111
311210022211120002112212
4232222123223201213
51310103112220033
635003435034035
73422424112136
oct565233534147
9153284502485
1050104023143
111a281462199
12986389b91b
134956491795
1425d448b91d
151483a91748
hexbaa6eb867

50104023143 has 8 divisors (see below), whose sum is σ = 53103399120. Its totient is φ = 47110433920.

The previous prime is 50104023127. The next prime is 50104023187. The reversal of 50104023143 is 34132040105.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 50104023143 - 24 = 50104023127 is a prime.

It is a super-2 number, since 2×501040231432 (a number of 22 digits) contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (50104023103) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1428848 + ... + 1463493.

It is an arithmetic number, because the mean of its divisors is an integer number (6637924890).

Almost surely, 250104023143 is an apocalyptic number.

50104023143 is a deficient number, since it is larger than the sum of its proper divisors (2999375977).

50104023143 is a wasteful number, since it uses less digits than its factorization.

50104023143 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2893377.

The product of its (nonzero) digits is 1440, while the sum is 23.

Adding to 50104023143 its reverse (34132040105), we get a palindrome (84236063248).

The spelling of 50104023143 in words is "fifty billion, one hundred four million, twenty-three thousand, one hundred forty-three".

Divisors: 1 17 1019 17323 2892341 49169797 2947295479 50104023143