Base | Representation |
---|---|
bin | 100100100010001001011… |
… | …1010010001010010111111 |
3 | 122210000102110112022000022 |
4 | 1021010102322101102333 |
5 | 1124231240303042421 |
6 | 14402402132122355 |
7 | 1025523245042006 |
oct | 111042272212277 |
9 | 18700373468008 |
10 | 5021134034111 |
11 | 16664a6297158 |
12 | 6911677663bb |
13 | 2a564c6a7ab0 |
14 | 13504a509c3d |
15 | 8a927ce77ab |
hex | 49112e914bf |
5021134034111 has 8 divisors (see below), whose sum is σ = 5408683512960. Its totient is φ = 4633771469472.
The previous prime is 5021134034101. The next prime is 5021134034143. The reversal of 5021134034111 is 1114304311205.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 5021134034111 - 26 = 5021134034047 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (5021134034101) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 46672751 + ... + 46780208.
It is an arithmetic number, because the mean of its divisors is an integer number (676085439120).
Almost surely, 25021134034111 is an apocalyptic number.
5021134034111 is a deficient number, since it is larger than the sum of its proper divisors (387549478849).
5021134034111 is a wasteful number, since it uses less digits than its factorization.
5021134034111 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 93457105.
The product of its (nonzero) digits is 1440, while the sum is 26.
Adding to 5021134034111 its reverse (1114304311205), we get a palindrome (6135438345316).
The spelling of 5021134034111 in words is "five trillion, twenty-one billion, one hundred thirty-four million, thirty-four thousand, one hundred eleven".
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