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5041301 = 23219187
BaseRepresentation
bin10011001110110010010101
3100111010100212
4103032302111
52242310201
6300015205
760564446
oct23166225
910433325
105041301
112933671
121831505
131076825
149532cd
15698abb
hex4cec95

5041301 has 4 divisors (see below), whose sum is σ = 5260512. Its totient is φ = 4822092.

The previous prime is 5041291. The next prime is 5041303. The reversal of 5041301 is 1031405.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 1031405 = 5206281.

It is a cyclic number.

It is not a de Polignac number, because 5041301 - 218 = 4779157 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (5041303) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 109571 + ... + 109616.

It is an arithmetic number, because the mean of its divisors is an integer number (1315128).

Almost surely, 25041301 is an apocalyptic number.

It is an amenable number.

5041301 is a deficient number, since it is larger than the sum of its proper divisors (219211).

5041301 is a wasteful number, since it uses less digits than its factorization.

5041301 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 219210.

The product of its (nonzero) digits is 60, while the sum is 14.

The square root of 5041301 is about 2245.2841690975. The cubic root of 5041301 is about 171.4671289924.

Adding to 5041301 its reverse (1031405), we get a palindrome (6072706).

The spelling of 5041301 in words is "five million, forty-one thousand, three hundred one".

Divisors: 1 23 219187 5041301