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505340433 = 32134319149
BaseRepresentation
bin11110000111101…
…110001000010001
31022012212221202100
4132013232020101
52013331343213
6122051111013
715344215503
oct3607561021
91265787670
10505340433
1123a284824
121212a2469
1380904b10
144b185d73
152e570773
hex1e1ee211

505340433 has 12 divisors (see below), whose sum is σ = 786085300. Its totient is φ = 310978656.

The previous prime is 505340411. The next prime is 505340447. The reversal of 505340433 is 334043505.

It is a happy number.

It can be written as a sum of positive squares in 2 ways, for example, as 83777409 + 421563024 = 9153^2 + 20532^2 .

It is not a de Polignac number, because 505340433 - 28 = 505340177 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 505340397 and 505340406.

It is not an unprimeable number, because it can be changed into a prime (505340333) by changing a digit.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 2159458 + ... + 2159691.

Almost surely, 2505340433 is an apocalyptic number.

It is an amenable number.

505340433 is a deficient number, since it is larger than the sum of its proper divisors (280744867).

505340433 is a wasteful number, since it uses less digits than its factorization.

505340433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4319168 (or 4319165 counting only the distinct ones).

The product of its (nonzero) digits is 10800, while the sum is 27.

The square root of 505340433 is about 22479.7783129639. The cubic root of 505340433 is about 796.5163275735.

Adding to 505340433 its reverse (334043505), we get a palindrome (839383938).

The spelling of 505340433 in words is "five hundred five million, three hundred forty thousand, four hundred thirty-three".

Divisors: 1 3 9 13 39 117 4319149 12957447 38872341 56148937 168446811 505340433