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51001110314300 = 2252510011103143
BaseRepresentation
bin10111001100010100111110…
…00100000011110100111100
320200120122210001211111111202
423212022133010003310330
523141100233220024200
6300245330413435032
713512465025612106
oct1346123704036474
9220518701744452
1051001110314300
11152834a41a3603
12587843479ba78
13225c4cba41113
14c846772b6576
155d69c8ae81d5
hex2e629f103d3c

51001110314300 has 18 divisors (see below), whose sum is σ = 110672409382248. Its totient is φ = 20400444125680.

The previous prime is 51001110314279. The next prime is 51001110314321. The reversal of 51001110314300 is 341301110015.

51001110314300 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is an interprime number because it is at equal distance from previous prime (51001110314279) and next prime (51001110314321).

It is a super-2 number, since 2×510011103143002 (a number of 28 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (20).

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 255005551472 + ... + 255005551671.

Almost surely, 251001110314300 is an apocalyptic number.

51001110314300 is a gapful number since it is divisible by the number (50) formed by its first and last digit.

It is an amenable number.

51001110314300 is an abundant number, since it is smaller than the sum of its proper divisors (59671299067948).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

51001110314300 is a wasteful number, since it uses less digits than its factorization.

51001110314300 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 510011103157 (or 510011103150 counting only the distinct ones).

The product of its (nonzero) digits is 180, while the sum is 20.

Adding to 51001110314300 its reverse (341301110015), we get a palindrome (51342411424315).

The spelling of 51001110314300 in words is "fifty-one trillion, one billion, one hundred ten million, three hundred fourteen thousand, three hundred".

Divisors: 1 2 4 5 10 20 25 50 100 510011103143 1020022206286 2040044412572 2550055515715 5100111031430 10200222062860 12750277578575 25500555157150 51001110314300