Base | Representation |
---|---|
bin | 101111100000011111… |
… | …101110111000011101 |
3 | 11212200001022002112021 |
4 | 233200133232320131 |
5 | 1313432312231013 |
6 | 35233435540141 |
7 | 3454046546233 |
oct | 574037567035 |
9 | 155601262467 |
10 | 51011055133 |
11 | 1a6a7457805 |
12 | 9a775ba651 |
13 | 4a6c37aabc |
14 | 267cb18953 |
15 | 14d850ba8d |
hex | be07eee1d |
51011055133 has 2 divisors, whose sum is σ = 51011055134. Its totient is φ = 51011055132.
The previous prime is 51011055097. The next prime is 51011055169. The reversal of 51011055133 is 33155011015.
It is a happy number.
It is a balanced prime because it is at equal distance from previous prime (51011055097) and next prime (51011055169).
It can be written as a sum of positive squares in only one way, i.e., 47125028889 + 3886026244 = 217083^2 + 62338^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-51011055133 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 51011055098 and 51011055107.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (51011050133) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25505527566 + 25505527567.
It is an arithmetic number, because the mean of its divisors is an integer number (25505527567).
Almost surely, 251011055133 is an apocalyptic number.
It is an amenable number.
51011055133 is a deficient number, since it is larger than the sum of its proper divisors (1).
51011055133 is an equidigital number, since it uses as much as digits as its factorization.
51011055133 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1125, while the sum is 25.
Adding to 51011055133 its reverse (33155011015), we get a palindrome (84166066148).
The spelling of 51011055133 in words is "fifty-one billion, eleven million, fifty-five thousand, one hundred thirty-three".
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