Base | Representation |
---|---|
bin | 101111100010011110… |
… | …100110100000100101 |
3 | 11212202100212202220202 |
4 | 233202132212200211 |
5 | 1314014321010000 |
6 | 35241024440245 |
7 | 3454632334301 |
oct | 574236464045 |
9 | 155670782822 |
10 | 51044313125 |
11 | 1a714202a53 |
12 | 9a86779085 |
13 | 4a762239a0 |
14 | 26832d4d01 |
15 | 14db3cadd5 |
hex | be27a6825 |
51044313125 has 20 divisors (see below), whose sum is σ = 68691521052. Its totient is φ = 37694256000.
The previous prime is 51044313113. The next prime is 51044313161. The reversal of 51044313125 is 52131344015.
51044313125 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It can be written as a sum of positive squares in 10 ways, for example, as 51025840321 + 18472804 = 225889^2 + 4298^2 .
It is a de Polignac number, because none of the positive numbers 2k-51044313125 is a prime.
It is a Duffinian number.
It is a Curzon number.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 19 ways as a sum of consecutive naturals, for example, 3133064 + ... + 3149313.
Almost surely, 251044313125 is an apocalyptic number.
It is an amenable number.
51044313125 is a deficient number, since it is larger than the sum of its proper divisors (17647207927).
51044313125 is an equidigital number, since it uses as much as digits as its factorization.
51044313125 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6282410 (or 6282395 counting only the distinct ones).
The product of its (nonzero) digits is 7200, while the sum is 29.
The spelling of 51044313125 in words is "fifty-one billion, forty-four million, three hundred thirteen thousand, one hundred twenty-five".
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