51044701 has 2 divisors, whose sum is σ = 51044702. Its totient is φ = 51044700.

The previous prime is 51044681. The next prime is 51044711. The reversal of 51044701 is 10744015.

51044701 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 28100601 + 22944100 = 5301^2 + 4790^2 .

It is a cyclic number.

It is not a de Polignac number, because 51044701 - 2⁷ = 51044573 is a prime.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (51044711) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25522350 + 25522351.

It is an arithmetic number, because the mean of its divisors is an integer number (25522351).

Almost surely, 2^51044701 is an apocalyptic number.

It is an amenable number.

51044701 is a deficient number, since it is larger than the sum of its proper divisors (1).

51044701 is an equidigital number, since it uses as much as digits as its factorization.

51044701 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 560, while the sum is 22.

The square root of 51044701 is about 7144.5574390581. The cubic root of 51044701 is about 370.9512920316.

Adding to 51044701 its reverse (10744015), we get a palindrome (61788716).

The spelling of 51044701 in words is "fifty-one million, forty-four thousand, seven hundred one".