Base | Representation |
---|---|
bin | 10111001101110101101000… |
… | …00111011100101000011111 |
3 | 20200202121201120022202002111 |
4 | 23212322310013130220133 |
5 | 23142423022300201143 |
6 | 300325231552534451 |
7 | 13516313003360116 |
oct | 1346726407345037 |
9 | 220677646282074 |
10 | 51053003131423 |
11 | 152a3503356127 |
12 | 58864b7551427 |
13 | 226437b99b177 |
14 | c86d9b160c7d |
15 | 5d801472c99d |
hex | 2e6eb41dca1f |
51053003131423 has 2 divisors, whose sum is σ = 51053003131424. Its totient is φ = 51053003131422.
The previous prime is 51053003131421. The next prime is 51053003131453. The reversal of 51053003131423 is 32413130035015.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 51053003131423 - 21 = 51053003131421 is a prime.
Together with 51053003131421, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (51053003131421) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25526501565711 + 25526501565712.
It is an arithmetic number, because the mean of its divisors is an integer number (25526501565712).
Almost surely, 251053003131423 is an apocalyptic number.
51053003131423 is a deficient number, since it is larger than the sum of its proper divisors (1).
51053003131423 is an equidigital number, since it uses as much as digits as its factorization.
51053003131423 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 16200, while the sum is 31.
Adding to 51053003131423 its reverse (32413130035015), we get a palindrome (83466133166438).
The spelling of 51053003131423 in words is "fifty-one trillion, fifty-three billion, three million, one hundred thirty-one thousand, four hundred twenty-three".
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