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51100544533 is a prime number
BaseRepresentation
bin101111100101110101…
…000110111000010101
311212220021200121220111
4233211311012320111
51314123214411113
635250354003021
73456214314253
oct574565067025
9155807617814
1051100544533
111a742a1a495
129aa1576471
134a84a814cc
14268a9715d3
1514e12d713d
hexbe5d46e15

51100544533 has 2 divisors, whose sum is σ = 51100544534. Its totient is φ = 51100544532.

The previous prime is 51100544531. The next prime is 51100544543. The reversal of 51100544533 is 33544500115.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 46379068164 + 4721476369 = 215358^2 + 68713^2 .

It is a cyclic number.

It is not a de Polignac number, because 51100544533 - 21 = 51100544531 is a prime.

It is a super-2 number, since 2×511005445332 (a number of 22 digits) contains 22 as substring.

Together with 51100544531, it forms a pair of twin primes.

It is a junction number, because it is equal to n+sod(n) for n = 51100544495 and 51100544504.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (51100544531) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25550272266 + 25550272267.

It is an arithmetic number, because the mean of its divisors is an integer number (25550272267).

Almost surely, 251100544533 is an apocalyptic number.

It is an amenable number.

51100544533 is a deficient number, since it is larger than the sum of its proper divisors (1).

51100544533 is an equidigital number, since it uses as much as digits as its factorization.

51100544533 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 18000, while the sum is 31.

The spelling of 51100544533 in words is "fifty-one billion, one hundred million, five hundred forty-four thousand, five hundred thirty-three".