Base | Representation |
---|---|
bin | 100101001011101010111… |
… | …0000101101100001100111 |
3 | 200002112120202121012120211 |
4 | 1022113111300231201213 |
5 | 1132211344410300320 |
6 | 14511350204240251 |
7 | 1035131025646453 |
oct | 112272560554147 |
9 | 20075522535524 |
10 | 5110302431335 |
11 | 16a02a3551822 |
12 | 6a64b1b40087 |
13 | 2b0b9013080a |
14 | 1394a8bb3663 |
15 | 8cde615855a |
hex | 4a5d5c2d867 |
5110302431335 has 8 divisors (see below), whose sum is σ = 6216367889520. Its totient is φ = 4032238630464.
The previous prime is 5110302431107. The next prime is 5110302431357. The reversal of 5110302431335 is 5331342030115.
It is a happy number.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 5110302431335 - 223 = 5110294042727 is a prime.
It is a super-2 number, since 2×51103024313352 (a number of 26 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 5110302431297 and 5110302431306.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 7000413925 + ... + 7000414654.
It is an arithmetic number, because the mean of its divisors is an integer number (777045986190).
Almost surely, 25110302431335 is an apocalyptic number.
5110302431335 is a deficient number, since it is larger than the sum of its proper divisors (1106065458185).
5110302431335 is a wasteful number, since it uses less digits than its factorization.
5110302431335 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 14000828657.
The product of its (nonzero) digits is 16200, while the sum is 31.
The spelling of 5110302431335 in words is "five trillion, one hundred ten billion, three hundred two million, four hundred thirty-one thousand, three hundred thirty-five".
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