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51110142356031 = 3112140799290237
BaseRepresentation
bin10111001111100000000011…
…11000010010101000111111
320200222002012200212002202120
423213300001320102220333
523144342032420343111
6300411401504454023
713523404654642563
oct1347600170225077
9220862180762676
1051110142356031
1115315764a15300
1258955a331a313
13226988683c245
14c89a5bacd6a3
155d975ac3d406
hex2e7c01e12a3f

51110142356031 has 12 divisors (see below), whose sum is σ = 74905222406616. Its totient is φ = 30975843851920.

The previous prime is 51110142355901. The next prime is 51110142356047. The reversal of 51110142356031 is 13065324101115.

It is a happy number.

51110142356031 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is not a de Polignac number, because 51110142356031 - 213 = 51110142347839 is a prime.

It is a super-3 number, since 3×511101423560313 (a number of 42 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Harshad number since it is a multiple of its sum of digits (33).

It is a junction number, because it is equal to n+sod(n) for n = 51110142355983 and 51110142356001.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (51110142356731) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 70399644756 + ... + 70399645481.

It is an arithmetic number, because the mean of its divisors is an integer number (6242101867218).

Almost surely, 251110142356031 is an apocalyptic number.

51110142356031 is a deficient number, since it is larger than the sum of its proper divisors (23795080050585).

51110142356031 is a wasteful number, since it uses less digits than its factorization.

51110142356031 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 140799290262 (or 140799290251 counting only the distinct ones).

The product of its (nonzero) digits is 10800, while the sum is 33.

Adding to 51110142356031 its reverse (13065324101115), we get a palindrome (64175466457146).

The spelling of 51110142356031 in words is "fifty-one trillion, one hundred ten billion, one hundred forty-two million, three hundred fifty-six thousand, thirty-one".

Divisors: 1 3 11 33 121 363 140799290237 422397870711 1548792192607 4646376577821 17036714118677 51110142356031