Base | Representation |
---|---|
bin | 1001100001010011… |
… | …01111000110100111 |
3 | 111012012122121011212 |
4 | 10300221233012213 |
5 | 40431432331003 |
6 | 2203103022035 |
7 | 240442415003 |
oct | 46051570647 |
9 | 14165577155 |
10 | 5111214503 |
11 | 219316911a |
12 | ba789a91b |
13 | 635bca9a5 |
14 | 366b71703 |
15 | 1edac3dd8 |
hex | 130a6f1a7 |
5111214503 has 2 divisors, whose sum is σ = 5111214504. Its totient is φ = 5111214502.
The previous prime is 5111214473. The next prime is 5111214539. The reversal of 5111214503 is 3054121115.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 5111214503 - 26 = 5111214439 is a prime.
It is a super-2 number, since 2×51112145032 = 52249027391355074018, which contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5111214103) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2555607251 + 2555607252.
It is an arithmetic number, because the mean of its divisors is an integer number (2555607252).
Almost surely, 25111214503 is an apocalyptic number.
5111214503 is a deficient number, since it is larger than the sum of its proper divisors (1).
5111214503 is an equidigital number, since it uses as much as digits as its factorization.
5111214503 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 600, while the sum is 23.
The square root of 5111214503 is about 71492.7583955186. The cubic root of 5111214503 is about 1722.5613657751.
Adding to 5111214503 its reverse (3054121115), we get a palindrome (8165335618).
The spelling of 5111214503 in words is "five billion, one hundred eleven million, two hundred fourteen thousand, five hundred three".
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