Base | Representation |
---|---|
bin | 1001100001010100… |
… | …00111100001100111 |
3 | 111012012211200101202 |
4 | 10300222013201213 |
5 | 40431444031120 |
6 | 2203105113115 |
7 | 240443312435 |
oct | 46052074147 |
9 | 14165750352 |
10 | 5111314535 |
11 | 2193227298 |
12 | ba792879b |
13 | 635c34392 |
14 | 366b99d55 |
15 | 1edae3875 |
hex | 130a87867 |
5111314535 has 8 divisors (see below), whose sum is σ = 6165358800. Its totient is φ = 4067864064.
The previous prime is 5111314499. The next prime is 5111314543. The reversal of 5111314535 is 5354131115.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 5111314535 - 212 = 5111310439 is a prime.
It is a super-2 number, since 2×51113145352 = 52251072551404532450, which contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 5111314498 and 5111314507.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2647385 + ... + 2649314.
It is an arithmetic number, because the mean of its divisors is an integer number (770669850).
Almost surely, 25111314535 is an apocalyptic number.
5111314535 is a deficient number, since it is larger than the sum of its proper divisors (1054044265).
5111314535 is a wasteful number, since it uses less digits than its factorization.
5111314535 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 5296897.
The product of its digits is 4500, while the sum is 29.
The square root of 5111314535 is about 71493.4579874271. The cubic root of 5111314535 is about 1722.5726031653.
The spelling of 5111314535 in words is "five billion, one hundred eleven million, three hundred fourteen thousand, five hundred thirty-five".
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