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5111325453445 = 51022265090689
BaseRepresentation
bin100101001100001001010…
…1111001110110010000101
3200002122020001121010002121
41022120102233032302011
51132220443304002240
614512035511205541
71035165260334301
oct112302257166205
920078201533077
105111325453445
1116a0778a6a442
126a67386768b1
132b0cc406b843
141395649d4d01
158ce55d8604a
hex4a612bcec85

5111325453445 has 4 divisors (see below), whose sum is σ = 6133590544140. Its totient is φ = 4089060362752.

The previous prime is 5111325453433. The next prime is 5111325453503. The reversal of 5111325453445 is 5443545231115.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 2399131481569 + 2712193971876 = 1548913^2 + 1646874^2 .

It is a cyclic number.

It is not a de Polignac number, because 5111325453445 - 225 = 5111291899013 is a prime.

It is a super-2 number, since 2×51113254534452 (a number of 26 digits) contains 22 as substring.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 511132545340 + ... + 511132545349.

It is an arithmetic number, because the mean of its divisors is an integer number (1533397636035).

Almost surely, 25111325453445 is an apocalyptic number.

It is an amenable number.

5111325453445 is a deficient number, since it is larger than the sum of its proper divisors (1022265090695).

5111325453445 is a wasteful number, since it uses less digits than its factorization.

5111325453445 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1022265090694.

The product of its digits is 720000, while the sum is 43.

The spelling of 5111325453445 in words is "five trillion, one hundred eleven billion, three hundred twenty-five million, four hundred fifty-three thousand, four hundred forty-five".

Divisors: 1 5 1022265090689 5111325453445