Base | Representation |
---|---|
bin | 100101001100001011100… |
… | …1101100100001100011111 |
3 | 200002122102021211121021120 |
4 | 1022120113031210030133 |
5 | 1132221122012424320 |
6 | 14512051152102023 |
7 | 1035200161336563 |
oct | 112302715441437 |
9 | 20078367747246 |
10 | 5111400514335 |
11 | 16a0807377835 |
12 | 6a6759834913 |
13 | 2b100678ca7b |
14 | 1395709736a3 |
15 | 8ce5c761440 |
hex | 4a61736431f |
5111400514335 has 16 divisors (see below), whose sum is σ = 8181664170720. Its totient is φ = 2724939158400.
The previous prime is 5111400514327. The next prime is 5111400514373. The reversal of 5111400514335 is 5334150041115.
It is a happy number.
It is not a de Polignac number, because 5111400514335 - 23 = 5111400514327 is a prime.
It is a super-2 number, since 2×51114005143352 (a number of 26 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 5111400514296 and 5111400514305.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 71282716 + ... + 71354385.
It is an arithmetic number, because the mean of its divisors is an integer number (511354010670).
Almost surely, 25111400514335 is an apocalyptic number.
5111400514335 is a deficient number, since it is larger than the sum of its proper divisors (3070263656385).
5111400514335 is a wasteful number, since it uses less digits than its factorization.
5111400514335 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 142639498.
The product of its (nonzero) digits is 18000, while the sum is 33.
The spelling of 5111400514335 in words is "five trillion, one hundred eleven billion, four hundred million, five hundred fourteen thousand, three hundred thirty-five".
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