Base | Representation |
---|---|
bin | 1001100001011011… |
… | …11000101000100011 |
3 | 111012021200212002210 |
4 | 10300231320220203 |
5 | 40432222131430 |
6 | 2203142213203 |
7 | 240454564614 |
oct | 46055705043 |
9 | 14167625083 |
10 | 5112302115 |
11 | 2193841278 |
12 | ba8124203 |
13 | 6361bba4b |
14 | 366d75c0b |
15 | 1edc3b2b0 |
hex | 130b78a23 |
5112302115 has 32 divisors (see below), whose sum is σ = 8643409920. Its totient is φ = 2574988416.
The previous prime is 5112302081. The next prime is 5112302123. The reversal of 5112302115 is 5112032115.
5112302115 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 5112302115 - 212 = 5112298019 is a prime.
It is a super-2 number, since 2×51123021152 = 52271265830066946450, which contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 5112302091 and 5112302100.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 66532 + ... + 121041.
It is an arithmetic number, because the mean of its divisors is an integer number (270106560).
Almost surely, 25112302115 is an apocalyptic number.
5112302115 is a deficient number, since it is larger than the sum of its proper divisors (3531107805).
5112302115 is a wasteful number, since it uses less digits than its factorization.
5112302115 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 187683.
The product of its (nonzero) digits is 300, while the sum is 21.
The square root of 5112302115 is about 71500.3644396307. The cubic root of 5112302115 is about 1722.6835380130.
The spelling of 5112302115 in words is "five billion, one hundred twelve million, three hundred two thousand, one hundred fifteen".
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