Base | Representation |
---|---|
bin | 10111001111111100100000… |
… | …01001000101100100011100 |
3 | 20201000112122000012021220022 |
4 | 23213332100021011210130 |
5 | 23200114321442304000 |
6 | 300422405125411312 |
7 | 13524455263665353 |
oct | 1347762011054434 |
9 | 221015560167808 |
10 | 51125414025500 |
11 | 15321191420641 |
12 | 5898545869b38 |
13 | 226b14b746c59 |
14 | c8a6aa03099a |
15 | 5d9d51817585 |
hex | 2e7f9024591c |
51125414025500 has 144 divisors (see below), whose sum is σ = 120351275501184. Its totient is φ = 18961628572800.
The previous prime is 51125414025463. The next prime is 51125414025509. The reversal of 51125414025500 is 552041452115.
It is a super-2 number, since 2×511254140255002 (a number of 28 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (51125414025509) by changing a digit.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 5470274 + ... + 11496726.
It is an arithmetic number, because the mean of its divisors is an integer number (835772746536).
Almost surely, 251125414025500 is an apocalyptic number.
51125414025500 is a gapful number since it is divisible by the number (50) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 51125414025500, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (60175637750592).
51125414025500 is an abundant number, since it is smaller than the sum of its proper divisors (69225861475684).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
51125414025500 is a wasteful number, since it uses less digits than its factorization.
51125414025500 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6026557 (or 6026526 counting only the distinct ones).
The product of its (nonzero) digits is 40000, while the sum is 35.
Adding to 51125414025500 its reverse (552041452115), we get a palindrome (51677455477615).
The spelling of 51125414025500 in words is "fifty-one trillion, one hundred twenty-five billion, four hundred fourteen million, twenty-five thousand, five hundred".
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