Base | Representation |
---|---|
bin | 1100001100001… |
… | …0110010010101 |
3 | 10120012122110221 |
4 | 3003002302111 |
5 | 101042120433 |
6 | 5023514341 |
7 | 1160410402 |
oct | 303026225 |
9 | 116178427 |
10 | 51129493 |
11 | 26952388 |
12 | 151589b1 |
13 | a79254c |
14 | 6b0d2a9 |
15 | 474e72d |
hex | 30c2c95 |
51129493 has 2 divisors, whose sum is σ = 51129494. Its totient is φ = 51129492.
The previous prime is 51129479. The next prime is 51129497. The reversal of 51129493 is 39492115.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 30272004 + 20857489 = 5502^2 + 4567^2 .
It is a cyclic number.
It is not a de Polignac number, because 51129493 - 217 = 50998421 is a prime.
It is a super-2 number, since 2×511294932 = 5228450108874098, which contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (51129497) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (11) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25564746 + 25564747.
It is an arithmetic number, because the mean of its divisors is an integer number (25564747).
Almost surely, 251129493 is an apocalyptic number.
It is an amenable number.
51129493 is a deficient number, since it is larger than the sum of its proper divisors (1).
51129493 is an equidigital number, since it uses as much as digits as its factorization.
51129493 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 9720, while the sum is 34.
The square root of 51129493 is about 7150.4890042570. The cubic root of 51129493 is about 371.1565781249.
It can be divided in two parts, 5 and 1129493, that multiplied together give a palindrome (5647465).
The spelling of 51129493 in words is "fifty-one million, one hundred twenty-nine thousand, four hundred ninety-three".
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