Base | Representation |
---|---|
bin | 100101001100111011101… |
… | …0100110111111110101000 |
3 | 200002210120200002112220121 |
4 | 1022121313110313332220 |
5 | 1132232422314334422 |
6 | 14512515154133024 |
7 | 1035255141530632 |
oct | 112316724677650 |
9 | 20083520075817 |
10 | 5113013043112 |
11 | 16a1464626547 |
12 | 6a6b29881174 |
13 | 2b1202891400 |
14 | 139684ba9a52 |
15 | 8d0040d78c7 |
hex | 4a677537fa8 |
5113013043112 has 48 divisors (see below), whose sum is σ = 10381726152000. Its totient is φ = 2359705398336.
The previous prime is 5113013043109. The next prime is 5113013043119. The reversal of 5113013043112 is 2113403103115.
It is a super-2 number, since 2×51130130431122 (a number of 26 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (5113013043119) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 23360439 + ... + 23578297.
It is an arithmetic number, because the mean of its divisors is an integer number (216285961500).
Almost surely, 25113013043112 is an apocalyptic number.
5113013043112 is a gapful number since it is divisible by the number (52) formed by its first and last digit.
It is an amenable number.
5113013043112 is an abundant number, since it is smaller than the sum of its proper divisors (5268713108888).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
5113013043112 is a wasteful number, since it uses less digits than its factorization.
5113013043112 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 235250 (or 235233 counting only the distinct ones).
The product of its (nonzero) digits is 1080, while the sum is 25.
Adding to 5113013043112 its reverse (2113403103115), we get a palindrome (7226416146227).
The spelling of 5113013043112 in words is "five trillion, one hundred thirteen billion, thirteen million, forty-three thousand, one hundred twelve".
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