Base | Representation |
---|---|
bin | 100101001101000010110… |
… | …0001000000000101111111 |
3 | 200002211012021001020211022 |
4 | 1022122011201000011333 |
5 | 1132233414240244403 |
6 | 14512554540414355 |
7 | 1035264062153243 |
oct | 112320541000577 |
9 | 20084167036738 |
10 | 5113251103103 |
11 | 16a1576a44540 |
12 | 6a6b955473bb |
13 | 2b123ccb3200 |
14 | 1396a8658423 |
15 | 8d019e5dd38 |
hex | 4a68584017f |
5113251103103 has 12 divisors (see below), whose sum is σ = 6040182585528. Its totient is φ = 4290840084960.
The previous prime is 5113251103061. The next prime is 5113251103127. The reversal of 5113251103103 is 3013011523115.
It is a happy number.
It is not a de Polignac number, because 5113251103103 - 28 = 5113251102847 is a prime.
It is a super-2 number, since 2×51132511031032 (a number of 26 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (5113251103133) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 1375267400 + ... + 1375271117.
It is an arithmetic number, because the mean of its divisors is an integer number (503348548794).
Almost surely, 25113251103103 is an apocalyptic number.
5113251103103 is a deficient number, since it is larger than the sum of its proper divisors (926931482425).
5113251103103 is a wasteful number, since it uses less digits than its factorization.
5113251103103 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2750538554 (or 2750538541 counting only the distinct ones).
The product of its (nonzero) digits is 1350, while the sum is 26.
Adding to 5113251103103 its reverse (3013011523115), we get a palindrome (8126262626218).
The spelling of 5113251103103 in words is "five trillion, one hundred thirteen billion, two hundred fifty-one million, one hundred three thousand, one hundred three".
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