Base | Representation |
---|---|
bin | 1100001100001… |
… | …1111010111101 |
3 | 10120012212212002 |
4 | 3003003322331 |
5 | 101042243031 |
6 | 5023552045 |
7 | 1160430062 |
oct | 303037275 |
9 | 116185762 |
10 | 51134141 |
11 | 26955923 |
12 | 1515b625 |
13 | a7946b6 |
14 | 6b10c69 |
15 | 4750ccb |
hex | 30c3ebd |
51134141 has 2 divisors, whose sum is σ = 51134142. Its totient is φ = 51134140.
The previous prime is 51134119. The next prime is 51134143. The reversal of 51134141 is 14143115.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 44222500 + 6911641 = 6650^2 + 2629^2 .
It is a cyclic number.
It is not a de Polignac number, because 51134141 - 26 = 51134077 is a prime.
It is a super-2 number, since 2×511341412 = 5229400751615762, which contains 22 as substring.
Together with 51134143, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (51134143) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25567070 + 25567071.
It is an arithmetic number, because the mean of its divisors is an integer number (25567071).
Almost surely, 251134141 is an apocalyptic number.
It is an amenable number.
51134141 is a deficient number, since it is larger than the sum of its proper divisors (1).
51134141 is an equidigital number, since it uses as much as digits as its factorization.
51134141 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 240, while the sum is 20.
The square root of 51134141 is about 7150.8140096076. The cubic root of 51134141 is about 371.1678246247.
Adding to 51134141 its reverse (14143115), we get a palindrome (65277256).
The spelling of 51134141 in words is "fifty-one million, one hundred thirty-four thousand, one hundred forty-one".
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