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51140147 is a prime number
BaseRepresentation
bin1100001100010…
…1011000110011
310120020012002112
43003011120303
5101042441042
65024035535
71160453432
oct303053063
9116205075
1051140147
112695a393
1215162bab
13a797356
146b13119
154752982
hex30c5633

51140147 has 2 divisors, whose sum is σ = 51140148. Its totient is φ = 51140146.

The previous prime is 51140129. The next prime is 51140171. The reversal of 51140147 is 74104115.

It is a happy number.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 51140147 - 26 = 51140083 is a prime.

It is a Chen prime.

It is equal to p3065351 and since 51140147 and 3065351 have the same sum of digits, it is a Honaker prime.

It is not a weakly prime, because it can be changed into another prime (51140107) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25570073 + 25570074.

It is an arithmetic number, because the mean of its divisors is an integer number (25570074).

Almost surely, 251140147 is an apocalyptic number.

51140147 is a deficient number, since it is larger than the sum of its proper divisors (1).

51140147 is an equidigital number, since it uses as much as digits as its factorization.

51140147 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 560, while the sum is 23.

The square root of 51140147 is about 7151.2339494663. The cubic root of 51140147 is about 371.1823559902.

The spelling of 51140147 in words is "fifty-one million, one hundred forty thousand, one hundred forty-seven".