51141214231 has 2 divisors, whose sum is σ = 51141214232. Its totient is φ = 51141214230.

The previous prime is 51141214183. The next prime is 51141214277. The reversal of 51141214231 is 13241214115.

It is a happy number.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 51141214231 - 2⁹ = 51141213719 is a prime.

It is a super-2 number, since 2×51141214231² (a number of 22 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 51141214196 and 51141214205.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (51141274231) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25570607115 + 25570607116.

It is an arithmetic number, because the mean of its divisors is an integer number (25570607116).

Almost surely, 2^51141214231 is an apocalyptic number.

51141214231 is a deficient number, since it is larger than the sum of its proper divisors (1).

51141214231 is an equidigital number, since it uses as much as digits as its factorization.

51141214231 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 960, while the sum is 25.

Adding to 51141214231 its reverse (13241214115), we get a palindrome (64382428346).

The spelling of 51141214231 in words is "fifty-one billion, one hundred forty-one million, two hundred fourteen thousand, two hundred thirty-one".