Base | Representation |
---|---|
bin | 1001100001101001… |
… | …11001011110111001 |
3 | 111012102011021000212 |
4 | 10300310321132321 |
5 | 40433204444401 |
6 | 2203245440505 |
7 | 240506322623 |
oct | 46064713671 |
9 | 14172137025 |
10 | 5114140601 |
11 | 2194887589 |
12 | ba8870135 |
13 | 6366b37cb |
14 | 3672d3c13 |
15 | 1edea0dbb |
hex | 130d397b9 |
5114140601 has 4 divisors (see below), whose sum is σ = 5139840000. Its totient is φ = 5088441204.
The previous prime is 5114140573. The next prime is 5114140613. The reversal of 5114140601 is 1060414115.
It is a happy number.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 1060414115 = 5 ⋅212082823.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-5114140601 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (5114140621) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 12849401 + ... + 12849798.
It is an arithmetic number, because the mean of its divisors is an integer number (1284960000).
Almost surely, 25114140601 is an apocalyptic number.
It is an amenable number.
5114140601 is a deficient number, since it is larger than the sum of its proper divisors (25699399).
5114140601 is a wasteful number, since it uses less digits than its factorization.
5114140601 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 25699398.
The product of its (nonzero) digits is 480, while the sum is 23.
The square root of 5114140601 is about 71513.2197639010. The cubic root of 5114140601 is about 1722.8900170719.
Adding to 5114140601 its reverse (1060414115), we get a palindrome (6174554716).
The spelling of 5114140601 in words is "five billion, one hundred fourteen million, one hundred forty thousand, six hundred one".
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