Base | Representation |
---|---|
bin | 1110111000100110011… |
… | …00010110101101110111 |
3 | 1210220001221211000220122 |
4 | 13130103030112231313 |
5 | 31334343304122403 |
6 | 1030540004122155 |
7 | 51643353513116 |
oct | 7342314265567 |
9 | 1726057730818 |
10 | 511423114103 |
11 | 187991019170 |
12 | 8314a69635b |
13 | 392c491a6a5 |
14 | 1aa78393c7d |
15 | d4838ee838 |
hex | 7713316b77 |
511423114103 has 4 divisors (see below), whose sum is σ = 557916124488. Its totient is φ = 464930103720.
The previous prime is 511423114043. The next prime is 511423114123. The reversal of 511423114103 is 301411324115.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 511423114103 - 28 = 511423113847 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (511423114123) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 23246505176 + ... + 23246505197.
It is an arithmetic number, because the mean of its divisors is an integer number (139479031122).
Almost surely, 2511423114103 is an apocalyptic number.
511423114103 is a deficient number, since it is larger than the sum of its proper divisors (46493010385).
511423114103 is a wasteful number, since it uses less digits than its factorization.
511423114103 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 46493010384.
The product of its (nonzero) digits is 1440, while the sum is 26.
Adding to 511423114103 its reverse (301411324115), we get a palindrome (812834438218).
It can be divided in two parts, 511423 and 114103, that added together give a palindrome (625526).
The spelling of 511423114103 in words is "five hundred eleven billion, four hundred twenty-three million, one hundred fourteen thousand, one hundred three".
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