Base | Representation |
---|---|
bin | 10111010000101100101000… |
… | …00110010100101010101000 |
3 | 20201010000022120112122001210 |
4 | 23220112110012110222220 |
5 | 23201030230023313134 |
6 | 300442320540513120 |
7 | 13526361443653635 |
oct | 1350262406245250 |
9 | 221100276478053 |
10 | 51151250213544 |
11 | 1533113a265068 |
12 | 58a155624b7a0 |
13 | 2270708293aa0 |
14 | c8ba3b48318c |
15 | 5da864b0e2e9 |
hex | 2e8594194aa8 |
51151250213544 has 32 divisors (see below), whose sum is σ = 137714904421920. Its totient is φ = 15738846219456.
The previous prime is 51151250213533. The next prime is 51151250213561. The reversal of 51151250213544 is 44531205215115.
It is a Harshad number since it is a multiple of its sum of digits (39).
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 81973157082 + ... + 81973157705.
It is an arithmetic number, because the mean of its divisors is an integer number (4303590763185).
Almost surely, 251151250213544 is an apocalyptic number.
It is an amenable number.
51151250213544 is an abundant number, since it is smaller than the sum of its proper divisors (86563654208376).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
51151250213544 is a wasteful number, since it uses less digits than its factorization.
51151250213544 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 163946314809 (or 163946314805 counting only the distinct ones).
The product of its (nonzero) digits is 120000, while the sum is 39.
Adding to 51151250213544 its reverse (44531205215115), we get a palindrome (95682455428659).
The spelling of 51151250213544 in words is "fifty-one trillion, one hundred fifty-one billion, two hundred fifty million, two hundred thirteen thousand, five hundred forty-four".
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