Base | Representation |
---|---|
bin | 1100001101010… |
… | …0010110010111 |
3 | 10120100022011022 |
4 | 3003110112113 |
5 | 101101421211 |
6 | 5025231355 |
7 | 1161130211 |
oct | 303242627 |
9 | 116308138 |
10 | 51201431 |
11 | 269a1436 |
12 | 1519255b |
13 | a7b9208 |
14 | 6b2b5b1 |
15 | 4765bdb |
hex | 30d4597 |
51201431 has 2 divisors, whose sum is σ = 51201432. Its totient is φ = 51201430.
The previous prime is 51201419. The next prime is 51201499. The reversal of 51201431 is 13410215.
51201431 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 51201431 - 214 = 51185047 is a prime.
It is a super-2 number, since 2×512014312 = 5243173072895522, which contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (51201131) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25600715 + 25600716.
It is an arithmetic number, because the mean of its divisors is an integer number (25600716).
Almost surely, 251201431 is an apocalyptic number.
51201431 is a deficient number, since it is larger than the sum of its proper divisors (1).
51201431 is an equidigital number, since it uses as much as digits as its factorization.
51201431 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 120, while the sum is 17.
The square root of 51201431 is about 7155.5175214655. The cubic root of 51201431 is about 371.3305660910.
Adding to 51201431 its reverse (13410215), we get a palindrome (64611646).
The spelling of 51201431 in words is "fifty-one million, two hundred one thousand, four hundred thirty-one".
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