Base | Representation |
---|---|
bin | 1110111001110111011… |
… | …11100100001110110111 |
3 | 1210221211100221211012010 |
4 | 13130323233210032313 |
5 | 31342241434330033 |
6 | 1031131305455303 |
7 | 51666254234421 |
oct | 7347357441667 |
9 | 1727740854163 |
10 | 512103433143 |
11 | 188200045a05 |
12 | 832ba4a1533 |
13 | 393a2858933 |
14 | 1ab00887811 |
15 | d4c34d5863 |
hex | 773bbe43b7 |
512103433143 has 4 divisors (see below), whose sum is σ = 682804577528. Its totient is φ = 341402288760.
The previous prime is 512103433139. The next prime is 512103433159. The reversal of 512103433143 is 341334301215.
It is a happy number.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 512103433143 - 22 = 512103433139 is a prime.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 512103433143.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (512103433043) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 85350572188 + ... + 85350572193.
It is an arithmetic number, because the mean of its divisors is an integer number (170701144382).
Almost surely, 2512103433143 is an apocalyptic number.
512103433143 is a deficient number, since it is larger than the sum of its proper divisors (170701144385).
512103433143 is a wasteful number, since it uses less digits than its factorization.
512103433143 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 170701144384.
The product of its (nonzero) digits is 12960, while the sum is 30.
Adding to 512103433143 its reverse (341334301215), we get a palindrome (853437734358).
The spelling of 512103433143 in words is "five hundred twelve billion, one hundred three million, four hundred thirty-three thousand, one hundred forty-three".
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