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51213240117 = 3313145906667
BaseRepresentation
bin101111101100100011…
…000000011100110101
311220012010202011012000
4233230203000130311
51314341042140432
635305501245513
73462053233644
oct575443003465
9156163664160
1051213240117
111a7a05a2336
129b13263899
134aa221b7a0
14269b90935b
1514eb14857c
hexbec8c0735

51213240117 has 16 divisors (see below), whose sum is σ = 81707734080. Its totient is φ = 31515839856.

The previous prime is 51213240103. The next prime is 51213240137. The reversal of 51213240117 is 71104231215.

51213240117 is a `hidden beast` number, since 512 + 1 + 32 + 4 + 0 + 117 = 666.

51213240117 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is not a de Polignac number, because 51213240117 - 24 = 51213240101 is a prime.

It is a Harshad number since it is a multiple of its sum of digits (27).

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (51213240137) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 72952983 + ... + 72953684.

It is an arithmetic number, because the mean of its divisors is an integer number (5106733380).

Almost surely, 251213240117 is an apocalyptic number.

It is an amenable number.

51213240117 is a deficient number, since it is larger than the sum of its proper divisors (30494493963).

51213240117 is a wasteful number, since it uses less digits than its factorization.

51213240117 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 145906689 (or 145906683 counting only the distinct ones).

The product of its (nonzero) digits is 1680, while the sum is 27.

The spelling of 51213240117 in words is "fifty-one billion, two hundred thirteen million, two hundred forty thousand, one hundred seventeen".

Divisors: 1 3 9 13 27 39 117 351 145906667 437720001 1313160003 1896786671 3939480009 5690360013 17071080039 51213240117