Base | Representation |
---|---|
bin | 10111010010110110100101… |
… | …01001010101101001110010 |
3 | 20201101002111012200000221121 |
4 | 23221123102221111221302 |
5 | 23203233420342232200 |
6 | 300540330121212454 |
7 | 13534623014654425 |
oct | 1351332251255162 |
9 | 221332435600847 |
10 | 51225314024050 |
11 | 1535a596364111 |
12 | 58b398603112a |
13 | 22776ac61232a |
14 | c91465a9d9bc |
15 | 5dc74bd9be1a |
hex | 2e96d2a55a72 |
51225314024050 has 24 divisors (see below), whose sum is σ = 95279715962352. Its totient is φ = 20489989722000.
The previous prime is 51225314024039. The next prime is 51225314024147. The reversal of 51225314024050 is 5042041352215.
It is a happy number.
It is a junction number, because it is equal to n+sod(n) for n = 51225314023997 and 51225314024015.
It is an unprimeable number.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 4394505 + ... + 11034595.
It is an arithmetic number, because the mean of its divisors is an integer number (3969988165098).
Almost surely, 251225314024050 is an apocalyptic number.
51225314024050 is a gapful number since it is divisible by the number (50) formed by its first and last digit.
51225314024050 is a deficient number, since it is larger than the sum of its proper divisors (44054401938302).
51225314024050 is a wasteful number, since it uses less digits than its factorization.
51225314024050 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6794394 (or 6794389 counting only the distinct ones).
The product of its (nonzero) digits is 48000, while the sum is 34.
Adding to 51225314024050 its reverse (5042041352215), we get a palindrome (56267355376265).
The spelling of 51225314024050 in words is "fifty-one trillion, two hundred twenty-five billion, three hundred fourteen million, twenty-four thousand, fifty".
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