Base | Representation |
---|---|
bin | 10111010011010100001110… |
… | …00001101010011011001001 |
3 | 20201102121120002100120220200 |
4 | 23221222013001222123021 |
5 | 23204014012122420403 |
6 | 300551521025042413 |
7 | 13536025220514435 |
oct | 1351520701523311 |
9 | 221377502316820 |
10 | 51241225201353 |
11 | 15366310852120 |
12 | 58b6a86786409 |
13 | 2279046b69445 |
14 | c92134d0d9c5 |
15 | 5dcd7db99ca3 |
hex | 2e9a8706a6c9 |
51241225201353 has 12 divisors (see below), whose sum is σ = 80743748802288. Its totient is φ = 31055288000760.
The previous prime is 51241225201321. The next prime is 51241225201433. The reversal of 51241225201353 is 35310252214215.
51241225201353 is a `hidden beast` number, since 5 + 1 + 2 + 4 + 122 + 520 + 1 + 3 + 5 + 3 = 666.
It is not a de Polignac number, because 51241225201353 - 25 = 51241225201321 is a prime.
It is not an unprimeable number, because it can be changed into a prime (51241225201253) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 258794066575 + ... + 258794066772.
It is an arithmetic number, because the mean of its divisors is an integer number (6728645733524).
Almost surely, 251241225201353 is an apocalyptic number.
It is an amenable number.
51241225201353 is a deficient number, since it is larger than the sum of its proper divisors (29502523600935).
51241225201353 is a wasteful number, since it uses less digits than its factorization.
51241225201353 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 517588133364 (or 517588133361 counting only the distinct ones).
The product of its (nonzero) digits is 72000, while the sum is 36.
Adding to 51241225201353 its reverse (35310252214215), we get a palindrome (86551477415568).
The spelling of 51241225201353 in words is "fifty-one trillion, two hundred forty-one billion, two hundred twenty-five million, two hundred one thousand, three hundred fifty-three".
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