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5124703 = 31165313
BaseRepresentation
bin10011100011001001011111
3100122100202211
4103203021133
52302442303
6301501251
761362553
oct23431137
910570684
105124703
1129902a1
121871827
1310a578c
14975863
156b366d
hex4e325f

5124703 has 4 divisors (see below), whose sum is σ = 5290048. Its totient is φ = 4959360.

The previous prime is 5124683. The next prime is 5124761. The reversal of 5124703 is 3074215.

5124703 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 3074215 = 5614843.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-5124703 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (5121703) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 82626 + ... + 82687.

It is an arithmetic number, because the mean of its divisors is an integer number (1322512).

Almost surely, 25124703 is an apocalyptic number.

5124703 is a deficient number, since it is larger than the sum of its proper divisors (165345).

5124703 is a wasteful number, since it uses less digits than its factorization.

5124703 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 165344.

The product of its (nonzero) digits is 840, while the sum is 22.

The square root of 5124703 is about 2263.7806872575. The cubic root of 5124703 is about 172.4075314816.

Adding to 5124703 its reverse (3074215), we get a palindrome (8198918).

The spelling of 5124703 in words is "five million, one hundred twenty-four thousand, seven hundred three".

Divisors: 1 31 165313 5124703