Base | Representation |
---|---|
bin | 10111010011101010001001… |
… | …11000100110011000101110 |
3 | 20201110201221201112020111210 |
4 | 23221311010320212120232 |
5 | 23204212121102244100 |
6 | 301001145305055250 |
7 | 13536623062356450 |
oct | 1351650470463056 |
9 | 221421851466453 |
10 | 51253000431150 |
11 | 153703036425a1 |
12 | 58b9212187526 |
13 | 227a1a258323b |
14 | c92930b3c2d0 |
15 | 5dd31c81bc50 |
hex | 2e9d44e2662e |
51253000431150 has 192 divisors, whose sum is σ = 145728297934848. Its totient is φ = 11677719231360.
The previous prime is 51253000431107. The next prime is 51253000431169. The reversal of 51253000431150 is 5113400035215.
51253000431150 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a Harshad number since it is a multiple of its sum of digits (30).
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 426681999 + ... + 426802101.
It is an arithmetic number, because the mean of its divisors is an integer number (759001551744).
Almost surely, 251253000431150 is an apocalyptic number.
51253000431150 is a gapful number since it is divisible by the number (50) formed by its first and last digit.
It is a practical number, because each smaller number is the sum of distinct divisors of 51253000431150, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (72864148967424).
51253000431150 is an abundant number, since it is smaller than the sum of its proper divisors (94475297503698).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
51253000431150 is a wasteful number, since it uses less digits than its factorization.
51253000431150 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 121415 (or 121410 counting only the distinct ones).
The product of its (nonzero) digits is 9000, while the sum is 30.
Adding to 51253000431150 its reverse (5113400035215), we get a palindrome (56366400466365).
The spelling of 51253000431150 in words is "fifty-one trillion, two hundred fifty-three billion, four hundred thirty-one thousand, one hundred fifty".
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