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51253000431150 = 23527547743120103
BaseRepresentation
bin10111010011101010001001…
…11000100110011000101110
320201110201221201112020111210
423221311010320212120232
523204212121102244100
6301001145305055250
713536623062356450
oct1351650470463056
9221421851466453
1051253000431150
11153703036425a1
1258b9212187526
13227a1a258323b
14c92930b3c2d0
155dd31c81bc50
hex2e9d44e2662e

51253000431150 has 192 divisors, whose sum is σ = 145728297934848. Its totient is φ = 11677719231360.

The previous prime is 51253000431107. The next prime is 51253000431169. The reversal of 51253000431150 is 5113400035215.

51253000431150 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a Harshad number since it is a multiple of its sum of digits (30).

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 426681999 + ... + 426802101.

It is an arithmetic number, because the mean of its divisors is an integer number (759001551744).

Almost surely, 251253000431150 is an apocalyptic number.

51253000431150 is a gapful number since it is divisible by the number (50) formed by its first and last digit.

It is a practical number, because each smaller number is the sum of distinct divisors of 51253000431150, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (72864148967424).

51253000431150 is an abundant number, since it is smaller than the sum of its proper divisors (94475297503698).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

51253000431150 is a wasteful number, since it uses less digits than its factorization.

51253000431150 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 121415 (or 121410 counting only the distinct ones).

The product of its (nonzero) digits is 9000, while the sum is 30.

Adding to 51253000431150 its reverse (5113400035215), we get a palindrome (56366400466365).

The spelling of 51253000431150 in words is "fifty-one trillion, two hundred fifty-three billion, four hundred thirty-one thousand, one hundred fifty".