Base | Representation |
---|---|
bin | 100101010100111001001… |
… | …1100100110001011010111 |
3 | 200011102201021000022121211 |
4 | 1022221302130212023113 |
5 | 1133022431412103310 |
6 | 14524423535522251 |
7 | 1036431635304556 |
oct | 112516234461327 |
9 | 20142637008554 |
10 | 5130111050455 |
11 | 16a8738a45526 |
12 | 6aa2bb989387 |
13 | 2b29c8c7b311 |
14 | 13a4278bbd9d |
15 | 8d6a51bdc8a |
hex | 4aa727262d7 |
5130111050455 has 64 divisors (see below), whose sum is σ = 6361814067840. Its totient is φ = 3969903052800.
The previous prime is 5130111050453. The next prime is 5130111050501. The reversal of 5130111050455 is 5540501110315.
It is a happy number.
It is not a de Polignac number, because 5130111050455 - 21 = 5130111050453 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (5130111050453) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 2756641225 + ... + 2756643085.
It is an arithmetic number, because the mean of its divisors is an integer number (99403344810).
Almost surely, 25130111050455 is an apocalyptic number.
5130111050455 is a deficient number, since it is larger than the sum of its proper divisors (1231703017385).
5130111050455 is a wasteful number, since it uses less digits than its factorization.
5130111050455 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2612.
The product of its (nonzero) digits is 7500, while the sum is 31.
The spelling of 5130111050455 in words is "five trillion, one hundred thirty billion, one hundred eleven million, fifty thousand, four hundred fifty-five".
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