Base | Representation |
---|---|
bin | 100101010100111001111… |
… | …0101011010000010001111 |
3 | 200011102202212211010021001 |
4 | 1022221303311122002033 |
5 | 1133023003342102120 |
6 | 14524430130521131 |
7 | 1036432340220463 |
oct | 112516365320217 |
9 | 20142685733231 |
10 | 5130134331535 |
11 | 16a87500a6994 |
12 | 6aa3077361a7 |
13 | 2b2a00a3ccc5 |
14 | 13a42aa1c4a3 |
15 | 8d6a726be0a |
hex | 4aa73d5a08f |
5130134331535 has 8 divisors (see below), whose sum is σ = 6165174615120. Its totient is φ = 4098098520384.
The previous prime is 5130134331521. The next prime is 5130134331601. The reversal of 5130134331535 is 5351334310315.
It is a happy number.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 5130134331535 - 239 = 4580378517647 is a prime.
It is a super-2 number, since 2×51301343315352 (a number of 26 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 5130134331494 and 5130134331503.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 751114350 + ... + 751121179.
It is an arithmetic number, because the mean of its divisors is an integer number (770646826890).
Almost surely, 25130134331535 is an apocalyptic number.
5130134331535 is a deficient number, since it is larger than the sum of its proper divisors (1035040283585).
5130134331535 is a wasteful number, since it uses less digits than its factorization.
5130134331535 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1502236217.
The product of its (nonzero) digits is 121500, while the sum is 37.
The spelling of 5130134331535 in words is "five trillion, one hundred thirty billion, one hundred thirty-four million, three hundred thirty-one thousand, five hundred thirty-five".
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