Base | Representation |
---|---|
bin | 1110111011111011100… |
… | …01101111101000110101 |
3 | 1211001200120121022100221 |
4 | 13131331301233220311 |
5 | 31402024043103110 |
6 | 1031433243134341 |
7 | 52035566035216 |
oct | 7357561575065 |
9 | 1731616538327 |
10 | 513211300405 |
11 | 188719443a91 |
12 | 835695143b1 |
13 | 3951b2324ab |
14 | 1aba7a7340d |
15 | d53a8c27da |
hex | 777dc6fa35 |
513211300405 has 8 divisors (see below), whose sum is σ = 616142842200. Its totient is φ = 410376185856.
The previous prime is 513211300363. The next prime is 513211300411. The reversal of 513211300405 is 504003112315.
It is a happy number.
It can be written as a sum of positive squares in 4 ways, for example, as 34002622404 + 479208678001 = 184398^2 + 692249^2 .
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 513211300405 - 211 = 513211298357 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 513211300405.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 24095100 + ... + 24116389.
It is an arithmetic number, because the mean of its divisors is an integer number (77017855275).
Almost surely, 2513211300405 is an apocalyptic number.
It is an amenable number.
513211300405 is a deficient number, since it is larger than the sum of its proper divisors (102931541795).
513211300405 is a wasteful number, since it uses less digits than its factorization.
513211300405 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 48213623.
The product of its (nonzero) digits is 1800, while the sum is 25.
The spelling of 513211300405 in words is "five hundred thirteen billion, two hundred eleven million, three hundred thousand, four hundred five".
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