Base | Representation |
---|---|
bin | 10111010110010101100011… |
… | …11000000100010101100101 |
3 | 20201210112110221211102102220 |
4 | 23223022301320010111211 |
5 | 23212214101432241240 |
6 | 301111324511022553 |
7 | 13546361354132400 |
oct | 1353126170042545 |
9 | 221715427742386 |
10 | 51345023321445 |
11 | 153a6336115047 |
12 | 591301450aa59 |
13 | 2285a79505709 |
14 | c97180572d37 |
15 | 5e090657d5d0 |
hex | 2eb2b1e04565 |
51345023321445 has 24 divisors (see below), whose sum is σ = 95564614836384. Its totient is φ = 23472010660896.
The previous prime is 51345023321437. The next prime is 51345023321507. The reversal of 51345023321445 is 54412332054315.
It is not a de Polignac number, because 51345023321445 - 23 = 51345023321437 is a prime.
It is a super-2 number, since 2×513450233214452 (a number of 28 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 51345023321397 and 51345023321406.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 34928586559 + ... + 34928588028.
It is an arithmetic number, because the mean of its divisors is an integer number (3981858951516).
Almost surely, 251345023321445 is an apocalyptic number.
It is an amenable number.
51345023321445 is a deficient number, since it is larger than the sum of its proper divisors (44219591514939).
51345023321445 is a wasteful number, since it uses less digits than its factorization.
51345023321445 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 69857174609 (or 69857174602 counting only the distinct ones).
The product of its (nonzero) digits is 864000, while the sum is 42.
The spelling of 51345023321445 in words is "fifty-one trillion, three hundred forty-five billion, twenty-three million, three hundred twenty-one thousand, four hundred forty-five".
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