Base | Representation |
---|---|
bin | 111010011000011011100001… |
… | …1100010111010101010010111 |
3 | 2111100021002101111210111002001 |
4 | 1310300313003202322222113 |
5 | 1014302143040114102120 |
6 | 5020104523325300131 |
7 | 213111252013561021 |
oct | 16460670342725227 |
9 | 2440232344714061 |
10 | 513531045456535 |
11 | 139699325484a57 |
12 | 49719910104647 |
13 | 19070a013264a2 |
14 | 90b506c8d1011 |
15 | 3e581c34a1e0a |
hex | 1d30dc38baa97 |
513531045456535 has 8 divisors (see below), whose sum is σ = 617195632863600. Its totient is φ = 410185917488064.
The previous prime is 513531045456521. The next prime is 513531045456589. The reversal of 513531045456535 is 535654540135315.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-513531045456535 is a prime.
It is a super-3 number, since 3×5135310454565353 (a number of 45 digits) contains 333 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 79864856110 + ... + 79864862539.
It is an arithmetic number, because the mean of its divisors is an integer number (77149454107950).
Almost surely, 2513531045456535 is an apocalyptic number.
513531045456535 is a deficient number, since it is larger than the sum of its proper divisors (103664587407065).
513531045456535 is a wasteful number, since it uses less digits than its factorization.
513531045456535 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 159729719297.
The product of its (nonzero) digits is 40500000, while the sum is 55.
The spelling of 513531045456535 in words is "five hundred thirteen trillion, five hundred thirty-one billion, forty-five million, four hundred fifty-six thousand, five hundred thirty-five".
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