Base | Representation |
---|---|
bin | 1001100101000110… |
… | …11010111011000101 |
3 | 111021102200020020222 |
4 | 10302203122323011 |
5 | 41013114112123 |
6 | 2210202434125 |
7 | 241310512514 |
oct | 46243327305 |
9 | 14242606228 |
10 | 5143113413 |
11 | 21aa176259 |
12 | bb6502945 |
13 | 63c6b9099 |
14 | 36b0b667b |
15 | 2017c56c8 |
hex | 1328daec5 |
5143113413 has 2 divisors, whose sum is σ = 5143113414. Its totient is φ = 5143113412.
The previous prime is 5143113397. The next prime is 5143113419. The reversal of 5143113413 is 3143113415.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 5020856164 + 122257249 = 70858^2 + 11057^2 .
It is a cyclic number.
It is not a de Polignac number, because 5143113413 - 24 = 5143113397 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5143113419) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2571556706 + 2571556707.
It is an arithmetic number, because the mean of its divisors is an integer number (2571556707).
Almost surely, 25143113413 is an apocalyptic number.
It is an amenable number.
5143113413 is a deficient number, since it is larger than the sum of its proper divisors (1).
5143113413 is an equidigital number, since it uses as much as digits as its factorization.
5143113413 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 2160, while the sum is 26.
The square root of 5143113413 is about 71715.5032960099. The cubic root of 5143113413 is about 1726.1374183603.
Adding to 5143113413 its reverse (3143113415), we get a palindrome (8286226828).
The spelling of 5143113413 in words is "five billion, one hundred forty-three million, one hundred thirteen thousand, four hundred thirteen".
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