51433121143 has 2 divisors, whose sum is σ = 51433121144. Its totient is φ = 51433121142.

The previous prime is 51433121141. The next prime is 51433121149. The reversal of 51433121143 is 34112133415.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 51433121143 - 2¹ = 51433121141 is a prime.

Together with 51433121141, it forms a pair of twin primes.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (51433121141) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25716560571 + 25716560572.

It is an arithmetic number, because the mean of its divisors is an integer number (25716560572).

Almost surely, 2^51433121143 is an apocalyptic number.

51433121143 is a deficient number, since it is larger than the sum of its proper divisors (1).

51433121143 is an equidigital number, since it uses as much as digits as its factorization.

51433121143 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 4320, while the sum is 28.

Adding to 51433121143 its reverse (34112133415), we get a palindrome (85545254558).

The spelling of 51433121143 in words is "fifty-one billion, four hundred thirty-three million, one hundred twenty-one thousand, one hundred forty-three".