Base | Representation |
---|---|
bin | 101111111001101010… |
… | …001011101100011111 |
3 | 11220202110200112200221 |
4 | 233321222023230133 |
5 | 1320313401144431 |
6 | 35343400302211 |
7 | 3500364125161 |
oct | 577152135437 |
9 | 156673615627 |
10 | 51433224991 |
11 | 1a8a3795215 |
12 | 9b74a71967 |
13 | 4b08982355 |
14 | 26bcc10931 |
15 | 15105ee111 |
hex | bf9a8bb1f |
51433224991 has 4 divisors (see below), whose sum is σ = 54458708832. Its totient is φ = 48407741152.
The previous prime is 51433224989. The next prime is 51433225009. The reversal of 51433224991 is 19942233415.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 51433224991 - 21 = 51433224989 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (51433224901) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1512741895 + ... + 1512741928.
It is an arithmetic number, because the mean of its divisors is an integer number (13614677208).
Almost surely, 251433224991 is an apocalyptic number.
51433224991 is a deficient number, since it is larger than the sum of its proper divisors (3025483841).
51433224991 is a wasteful number, since it uses less digits than its factorization.
51433224991 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 3025483840.
The product of its digits is 233280, while the sum is 43.
The spelling of 51433224991 in words is "fifty-one billion, four hundred thirty-three million, two hundred twenty-four thousand, nine hundred ninety-one".
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