Base | Representation |
---|---|
bin | 100101011011011010100… |
… | …0101101100011100000111 |
3 | 200012202212011001222121011 |
4 | 1022312311011230130013 |
5 | 1133240121142202101 |
6 | 14535101240103051 |
7 | 1040435640511126 |
oct | 112666505543407 |
9 | 20182764058534 |
10 | 5144114022151 |
11 | 1703674293405 |
12 | 6b0b69464a87 |
13 | 2b411b08a9a0 |
14 | 13ad95529abd |
15 | 8dc246dc751 |
hex | 4adb516c707 |
5144114022151 has 8 divisors (see below), whose sum is σ = 5609939343680. Its totient is φ = 4688306449632.
The previous prime is 5144114022067. The next prime is 5144114022241. The reversal of 5144114022151 is 1512204114415.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 5144114022151 - 213 = 5144114013959 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (5144114022451) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2504436180 + ... + 2504438233.
It is an arithmetic number, because the mean of its divisors is an integer number (701242417960).
Almost surely, 25144114022151 is an apocalyptic number.
5144114022151 is a deficient number, since it is larger than the sum of its proper divisors (465825321529).
5144114022151 is a wasteful number, since it uses less digits than its factorization.
5144114022151 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5008874505.
The product of its (nonzero) digits is 6400, while the sum is 31.
Adding to 5144114022151 its reverse (1512204114415), we get a palindrome (6656318136566).
The spelling of 5144114022151 in words is "five trillion, one hundred forty-four billion, one hundred fourteen million, twenty-two thousand, one hundred fifty-one".
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