Base | Representation |
---|---|
bin | 100101011011111000100… |
… | …1100100011111001011111 |
3 | 200012212110102121200120221 |
4 | 1022313301030203321133 |
5 | 1133244202322031020 |
6 | 14535345302222211 |
7 | 1040502634164025 |
oct | 112676114437137 |
9 | 20185412550527 |
10 | 5145122455135 |
11 | 1704041546aa3 |
12 | 6b11ab124967 |
13 | 2b424bc8b3b0 |
14 | 13b04d430715 |
15 | 8dc82ed76aa |
hex | 4adf1323e5f |
5145122455135 has 8 divisors (see below), whose sum is σ = 6649081326720. Its totient is φ = 3799475043744.
The previous prime is 5145122455133. The next prime is 5145122455157. The reversal of 5145122455135 is 5315542215415.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 5145122455135 - 21 = 5145122455133 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 5145122455091 and 5145122455100.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (5145122455133) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 39577864975 + ... + 39577865104.
It is an arithmetic number, because the mean of its divisors is an integer number (831135165840).
Almost surely, 25145122455135 is an apocalyptic number.
5145122455135 is a deficient number, since it is larger than the sum of its proper divisors (1503958871585).
5145122455135 is a wasteful number, since it uses less digits than its factorization.
5145122455135 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 79155730097.
The product of its digits is 600000, while the sum is 43.
The spelling of 5145122455135 in words is "five trillion, one hundred forty-five billion, one hundred twenty-two million, four hundred fifty-five thousand, one hundred thirty-five".
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