Base | Representation |
---|---|
bin | 110000000000101111… |
… | …101111100100000111 |
3 | 11221001202102012022012 |
4 | 300000233233210013 |
5 | 1321034320420033 |
6 | 35403244524435 |
7 | 3503336550053 |
oct | 600057574407 |
9 | 157052365265 |
10 | 51552123143 |
11 | 1a954914154 |
12 | 9ba885071b |
13 | 4b274b18a1 |
14 | 26d0920c63 |
15 | 151ac88248 |
hex | c00bef907 |
51552123143 has 4 divisors (see below), whose sum is σ = 51552587688. Its totient is φ = 51551658600.
The previous prime is 51552123109. The next prime is 51552123149. The reversal of 51552123143 is 34132125515.
It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length, and also an emirpimes, since its reverse is a distinct semiprime: 34132125515 = 5 ⋅6826425103.
It is a cyclic number.
It is not a de Polignac number, because 51552123143 - 226 = 51485014279 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (51552123149) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 42680 + ... + 323922.
It is an arithmetic number, because the mean of its divisors is an integer number (12888146922).
Almost surely, 251552123143 is an apocalyptic number.
51552123143 is a deficient number, since it is larger than the sum of its proper divisors (464545).
51552123143 is a wasteful number, since it uses less digits than its factorization.
51552123143 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 464544.
The product of its digits is 18000, while the sum is 32.
Adding to 51552123143 its reverse (34132125515), we get a palindrome (85684248658).
The spelling of 51552123143 in words is "fifty-one billion, five hundred fifty-two million, one hundred twenty-three thousand, one hundred forty-three".
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