Base | Representation |
---|---|
bin | 1111000010011111011… |
… | …01011101100010011111 |
3 | 1211101210001001011011212 |
4 | 13201033231131202133 |
5 | 31431232222034210 |
6 | 1033214541535035 |
7 | 52222064241005 |
oct | 7411755354237 |
9 | 1741701034155 |
10 | 516733393055 |
11 | 18a166590360 |
12 | 84190b7447b |
13 | 3995cb35899 |
14 | 1b01d742a75 |
15 | d694be5805 |
hex | 784fb5d89f |
516733393055 has 8 divisors (see below), whose sum is σ = 676450987344. Its totient is φ = 375806104000.
The previous prime is 516733393051. The next prime is 516733393067. The reversal of 516733393055 is 550393337615.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 516733393055 - 22 = 516733393051 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 516733392994 and 516733393012.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (516733393051) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 4697576246 + ... + 4697576355.
It is an arithmetic number, because the mean of its divisors is an integer number (84556373418).
Almost surely, 2516733393055 is an apocalyptic number.
516733393055 is a gapful number since it is divisible by the number (55) formed by its first and last digit.
516733393055 is a deficient number, since it is larger than the sum of its proper divisors (159717594289).
516733393055 is a wasteful number, since it uses less digits than its factorization.
516733393055 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 9395152617.
The product of its (nonzero) digits is 3827250, while the sum is 50.
The spelling of 516733393055 in words is "five hundred sixteen billion, seven hundred thirty-three million, three hundred ninety-three thousand, fifty-five".
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