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5200103 is a prime number
BaseRepresentation
bin10011110101100011100111
3100210012012102
4103311203213
52312400403
6303242315
762125436
oct23654347
910705172
105200103
112a31a07
1218a939b
131100bac
1499511d
156cab88
hex4f58e7

5200103 has 2 divisors, whose sum is σ = 5200104. Its totient is φ = 5200102.

The previous prime is 5200099. The next prime is 5200123. The reversal of 5200103 is 3010025.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 5200103 - 22 = 5200099 is a prime.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (5200123) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2600051 + 2600052.

It is an arithmetic number, because the mean of its divisors is an integer number (2600052).

Almost surely, 25200103 is an apocalyptic number.

5200103 is a deficient number, since it is larger than the sum of its proper divisors (1).

5200103 is an equidigital number, since it uses as much as digits as its factorization.

5200103 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 30, while the sum is 11.

The square root of 5200103 is about 2280.3734343304. The cubic root of 5200103 is about 173.2489649405.

Adding to 5200103 its reverse (3010025), we get a palindrome (8210128).

The spelling of 5200103 in words is "five million, two hundred thousand, one hundred three".