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5211315335 = 51042263067
BaseRepresentation
bin1001101101001111…
…00101110010000111
3111110012000020201002
410312213211302013
541133044042320
62221040323515
7243066310112
oct46647456207
914405006632
105211315335
112234719386
12101531359b
13650878355
1437618b579
15207798675
hex1369e5c87

5211315335 has 4 divisors (see below), whose sum is σ = 6253578408. Its totient is φ = 4169052264.

The previous prime is 5211315311. The next prime is 5211315359. The reversal of 5211315335 is 5335131125.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is an interprime number because it is at equal distance from previous prime (5211315311) and next prime (5211315359).

It is a cyclic number.

It is not a de Polignac number, because 5211315335 - 212 = 5211311239 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 5211315298 and 5211315307.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 521131529 + ... + 521131538.

It is an arithmetic number, because the mean of its divisors is an integer number (1563394602).

Almost surely, 25211315335 is an apocalyptic number.

5211315335 is a deficient number, since it is larger than the sum of its proper divisors (1042263073).

5211315335 is a wasteful number, since it uses less digits than its factorization.

5211315335 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1042263072.

The product of its digits is 6750, while the sum is 29.

The square root of 5211315335 is about 72189.4406059501. The cubic root of 5211315335 is about 1733.7339394770.

The spelling of 5211315335 in words is "five billion, two hundred eleven million, three hundred fifteen thousand, three hundred thirty-five".

Divisors: 1 5 1042263067 5211315335